0=5x-4.095x^2

Solution for 0=5x-4.095x^2 equation:

0=5x-4.095x^2

We move all terms to the left:

0-(5x-4.095x^2)=0

We add all the numbers together, and all the variables

-(5x-4.095x^2)=0

We get rid of parentheses

4.095x^2-5x=0

a = 4.095; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·4.095·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*4.095}=\frac{0}{8.19}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*4.095}=\frac{10}{8.19}
=1+1/4.524861878453
$